2x^2+11x+9=10x+102x2+11x+9=10x+10

Solution for 2x^2+11x+9=10x+102x2+11x+9=10x+10 equation:

2x^2+11x+9=10x+102x^2+11x+9=10x+10

We move all terms to the left:

2x^2+11x+9-(10x+102x^2+11x+9)=0

We get rid of parentheses

2x^2-102x^2-10x-11x+11x-9+9=0

We add all the numbers together, and all the variables

-100x^2-10x=0

a = -100; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·(-100)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*-100}=\frac{0}{-200}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*-100}=\frac{20}{-200}
=-1/10
$